class SubarraySum {
/* Returns true if the there is
a subarray of arr[] with sum equal to
'sum' otherwise returns false.
Also, prints the result */
int subArraySum(int arr[], int n, int sum)
{
int currentSum = arr[0], start = 0, i;
// Pick a starting point
for (i = 1; i <= n; i++) {
// If currentSum exceeds the sum,
// then remove the starting elements
while (currentSum > sum && start < i - 1) {
currentSum = currentSum - arr[start];
start++;
}
// If currentSum becomes equal to sum,
// then return true
if (currentSum == sum) {
int p = i - 1;
System.out.println(
"Sum found between indexes " + start
+ " and " + p);
return 1;
}
// Add this element to curr_sum
if (i < n)
currentSum = currentSum + arr[i];
}
System.out.println("No subarray found");
return 0;
}
public static void main(String[] args)
{
SubarraySum arraysum = new SubarraySum();
int arr[] = { 15, 2, 4, 8, 9, 5, 10, 23 };
int n = arr.length;
int sum = 23;
arraysum.subArraySum(arr, n, sum);
}
}
// This code has been contributed by Mayank
// Jaiswal(mayank_24)