//HOW ABOUT MORE EFFICIENT SOLUTION
// BASIC IDEA- REPEATEDLY SWAP TWO ADJACENT ELEMENTS IF THEY ARE IN A WRONG ORDER.
#include<bits/stdc++.h>
using namespace std;
void bubblesort(int a[], int n)
{
bool swapped=false;
for(int i=0;i<n-1;i++)
{
for(int j=0;j<n-i-1;j++)
{
if(a[j]>a[j+1]) // check if ADJACENT elements are in a wrong order.
{
swap(a[j],a[j+1]); //if they are swap them.
swapped=true;
}
}
if(swapped==false) break; // if for any particular iteration our array doesn't swap--
// -- any numbers then we may conclude that our array has already been sorted. :)
}
}
int main()
{
int n;
cin>>n;
int a[n];
for(int i=0;i<n;i++) cin>>a[i];
bubblesort(a,n);
for(int i=0;i<n;i++) cout<<a[i]<<" ";
return 0;
}