// C program to check if a given
// year is leap year or not
#include <stdio.h>
#include <stdbool.h>
bool checkYear(int year)
{
// If a year is multiple of 400,
// then it is a leap year
if (year % 400 == 0)
return true;
// Else If a year is multiple of 100,
// then it is not a leap year
if (year % 100 == 0)
return false;
// Else If a year is multiple of 4,
// then it is a leap year
if (year % 4 == 0)
return true;
return false;
}
// driver code
int main()
{
int year = 2000;
checkYear(year)? printf("Leap Year"):
printf("Not a Leap Year");
return 0;
}
#include <stdio.h>
void
main ()
{
int year;
printf ("
enter year to be checked for leap");
scanf ("%d", &year);
if (year % 4 == 0)
{
printf ("
%d is leap year yay!", year);
}
else
{
printf ("
year enterd is not leap, waaa :-(");
}
}
#include<stdio.h>
int isLeapYear(int n);
int main(void) {
// TODO: Write your code here
int n, x;
printf("Enter year: ");
scanf("%d", &n);
if(isLeapYear(n)){
printf("%d is a leap year",n);
}else{
printf("%d is not a leap year",n);
}
return 0;
}
int isLeapYear(int n) {
if(
(n % 4 == 0 && n % 100 != 0) ||
(n % 100 == 0 && n % 400 == 0)
) {
return 1;
}
return 0;
}