#include <iostream>
using namespace std;
int main()
{
int i, j, n, sum = 0, tsum;
cout << "
Find the sum of the series (1) + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n):
";
cout << "------------------------------------------------------------------------------------------
";
cout << " Input the value for nth term: ";
cin >> n;
for (i = 1; i <= n; i++)
{
tsum = 0;
for (j = 1; j <= i; j++)
{
sum += j;
tsum += j;
cout << j;
if (j < i)
{
cout << "+";
}
}
cout << " = " << tsum << endl;
}
cout << " The sum of the above series is: " << sum << endl;
}
#include <stdio.h>
int main()
{
int num, max, min;
printf ("Enter four numbers: ");
scanf ("%d", &num);
max = min = num;
for (int i = 0; i < 3; i++)
{
scanf ("%d", &num);
if (max < num)
max = num;
else if (min > num)
min = num;
}
printf ("The smallest and largest of given four numbers are %d and %d respectively.
", min, max);
return 0;
}
#include <iostream>
using namespace std;
int main(){
int k,n,m;
cout<<"Introduceti numar n:";
cin>>n;
cout<<"Introduceti numar k:";
cin>>k;
//daca restul impartirii lui n la k
//este mai mic decat jumatate din impartitor
if(n%k<=k/2){
//atunci multiplul este cel mai mare multiplu mai mic decat n
m=k*(n/k);
}
else{
//altfel este cel mai mic multiplu mai mare decat n
m=k*(n/k+1);
}
cout<<"Multiplu "<<k<<" cel mai apropriat de "<<n<<" este "<<m;
return 0;
}