public int kadane(int[] arr){
int max_so_far = 0, curr_max = Integer.MIN_VALUE;
for(int i: arr){
max_so_far += i;
if(max_so_far<0) max_so_far = 0;
if(max_so_far>curr_max) curr_max = max_so_far;
}
return curr_max;
}
Lets take the example:
{-2, -3, 4, -1, -2, 1, 5, -3}
max_so_far = max_ending_here = 0
for i=0, a[0] = -2
max_ending_here = max_ending_here + (-2)
Set max_ending_here = 0 because max_ending_here < 0
for i=1, a[1] = -3
max_ending_here = max_ending_here + (-3)
Set max_ending_here = 0 because max_ending_here < 0
for i=2, a[2] = 4
max_ending_here = max_ending_here + (4)
max_ending_here = 4
max_so_far is updated to 4 because max_ending_here greater
than max_so_far which was 0 till now
for i=3, a[3] = -1
max_ending_here = max_ending_here + (-1)
max_ending_here = 3
for i=4, a[4] = -2
max_ending_here = max_ending_here + (-2)
max_ending_here = 1
for i=5, a[5] = 1
max_ending_here = max_ending_here + (1)
max_ending_here = 2
for i=6, a[6] = 5
max_ending_here = max_ending_here + (5)
max_ending_here = 7
max_so_far is updated to 7 because max_ending_here is
greater than max_so_far
for i=7, a[7] = -3
max_ending_here = max_ending_here + (-3)
max_ending_here = 4
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int curMax = 0, maxTillNow = INT_MIN;
for(auto c : nums)
curMax = max(c, curMax + c),
maxTillNow = max(maxTillNow, curMax);
return maxTillNow;
}
};