JAVASCRIPT

sort in javascript array

//sort is function in js which sort according to alphanumerical
//for array with number it is little twist
const items= ["Banana","Orange","Apple"];
const ratings = [92,52,2,22]
console.log(items.sort())// reuturn ["Apple","Banana","Orange]
//for array with number
ratings.sort(function(a,b){
return a-b; //ascending for decending b-a
// return is negative a is sorted befor b 
// positive b is sorted before a
// if they are the same is 0 then nothing changes.
})

sort method in js

// Sort method

// const arr = [3,53,423,534,3];
// console.log(arr.sort());

// const names = ["fahad", "taha", "salman", "mojeeb"]; // This looks good but if we solve this sort this like with capital letters it'll give first priority to capital letter then it'll sort small letters the example is given below

// names.sort();
// console.log(names);

// Example
// const namesWithCapitalLetters = ["fahad", "Taha", "salman", "mojeeb"];
// namesWithCapitalLetters.sort();

// console.log(namesWithCapitalLetters);

// That's how it works :)

// How to get expected output

// const arr = [3,53,423,534,3];
// console.log(arr.sort()); ---> We're not getting expected output while we're doing this but there is a way with that we can get our expected output

// The way

const arr = [3, 53, 423, 534, 3];
console.log(arr.sort((a, b) => a - b));

// How this is working questing is this?

// What javascript here doing is first javascript 3 and 52 a = 3 b = 52; And now if we 3 to 52 and we'll get number greater than 0 then javascript sort those numbers in order of b then a ---> like 52, 3 and if we got the output less than 0 then javascript sort the number in order of a, b ---> 3  52 and yes you're right this is the correct output :)

// A use case of sort method

// Imagine you have a ecommerce site and you want to sort products prices then how can you sort the prices of products with sort method example given below

// Example
const userCart = [
  { producdId: 1, producdPrice: 355 },
  { producdId: 2, producdPrice: 5355 },
  { producdId: 3, producdPrice: 34 },
  { producdId: 4, producdPrice: 3535 },
];

// Use this for low to high
userCart.sort((a, b) => a.producdPrice - b.producdPrice);

// console.log(userCart)

// ===================================

// Use this for high to low
userCart.sort((a, b) => b.producdPrice - a.producdPrice);

// console.log(userCart)

// ==============The End=================

sort array in javascript

//This method will be sort array in ascending order:
var numArray = [5, 10, 12, 9, 31, 21, 18, 55, 39, 40];
numArray.sort((a, b) => {
  return a - b;
});
console.log(numArray);

//This method will be sort array in descending order:
numArray.sort((a, b) => {
  return b - a;
});

console.log(numArray)

//sort array by date

// Name Z to A
array.sort((a, b) => (a.name > b.name ? -1 : 1))

console.log(array)
// Sort by date
array.sort((a,b) =>  new Date(a.date) - new Date(b.date));

console.log(array)

sort() function example JavaScript

function ascendingOrder(arr) {
  return arr.sort(function(a, b) {
    return a - b;
  });
}
ascendingOrder([1, 5, 2, 3, 4]);

Sort in array in Javascript

const ascending: any= values.sort((a,b) =>  (a > b ? 1 : -1));
const descending: any= values.sort((a,b) => (a > b ? -1 : 1))

javascript sorting an array

sorting an array

how to sort an array in js

//ascending order
let ArrayOne = [1,32,5341,10,32,10,90]
ArrayOne = ArrayOne.sort(function(x,y){x-y})
//descending order
let ArrayTwo = [321,51,51,324,111,1000]
ArrayTwo = ArrayTwo.sort(function(x,y){y-x})

Sorting in JavaScript

var l = ["a", "w", "r", "e", "d", "c", "e", "f", "g"];
console.log(l.sort())
/*[ 'a', 'c', 'd', 'e', 'e', 'f', 'g', 'r', 'w' ]*/

define array sort method in javascript

How does the following code sort this array to be in numerical order?     

    var array=[25, 8, 7, 41]

    array.sort(function(a,b){
      return a - b
    })

I know that if the result of the computation is... 

**Less than 0**: "a" is sorted to be a lower index than "b".<br />
**Zero:** "a" and "b" are considered equal, and no sorting is performed.<br />
**Greater than 0:** "b" is sorted to be a lower index than "a".<br />

Is the array sort callback function called many times during the course of the sort?

If so, I'd like to know which two numbers are passed into the function each time. I assumed it first took "25"(a) and "8"(b), followed by "7"(a) and "41"(b), so:

25(a) - 8(b) = 17 (greater than zero, so sort "b" to be a lower index than "a"): 8, 25

7(a) - 41(b) = -34 (less than zero, so sort "a" to be a lower index than "b": 7, 41

How are the two sets of numbers then sorted in relation to one another?

Please help a struggling newbie!

sort function explained javascript

var sortedArray = myArray.sort(function(a,b){
                                   if (a.name < b.name)
                                      return -1;
                                   else if (a.name == b.name)
                                      return 0;
                                   else
                                      return 1;
                               });

Sort List in JavaScript

let name = ["Daniyal","Ahmed","Irsam","Zulfaqar","Tariq"];
for(let i=0;i<name.length;i++){
    console.log("Name's Unsorted "+name[i]);
}

console.log("...............................Orignal Array..................................");
for(let i=0;i<name.length;i++){
    console.log("Name's Sorted: "+name[i]);
}