PYTHON

permutations python

import itertools
print(list(itertools.permutations([1,2,3])))

python permutation

import itertools

a = [1, 2, 3]
n = 3

perm_iterator = itertools.permutations(a, n)

for item in perm_iterator:
    print(item)

Using python permutations function on a list

from itertools import permutations
a=permutations([1,2,3,4],2) 
for i in a: 
   print(i)

Using Python Permutations function on a String

from itertools import permutations 
string="SOFT"
a=permutations(string) 
for i in list(a): 
   # join all the letters of the list to make a string 
   print("".join(i))

how to find permutation of numbers in python

def permute(LIST):
    length=len(LIST)
    if length <= 1:
        yield LIST
    else:
        for n in range(0,length):
             for end in permute( LIST[:n] + LIST[n+1:] ):
                 yield [ LIST[n] ] + end

for x in permute(["3","3","4"]):
    print x

all permutations python

import itertools
list(itertools.permutations([1, 2, 3]))

python all permutations of a string

>>> from itertools import permutations
>>> perms = [''.join(p) for p in permutations('stack')]
>>> perms

permutation python

def permutations(s):
    if len(s) <= 1: 
        yield s
    else:
        for i in range(len(s)):
            for p in permutations(s[:i] + s[i+1:]):
                yield s[i] + p
        
input = 'ABCD'

for permutation in enumerate(permutations(input)):
    print repr(permutation[1]),
print

Permutation in python

from itertools import permutations
from itertools import combinations
p = permutations([1,2,4]) # or  permutations([1, 2, 3], 2)
for i in p:
    print(i)
c = combinations([1,2,3],2)
for j in c:
    print(j)