x = np.array([[0,3],[2,2]])
>>> ind = np.argsort(x, axis=1) # sorts along last axis (across)
>>> ind
array([[0, 1],
[0, 1]])
>>> np.take_along_axis(x, ind, axis=1) # same as np.sort(x, axis=1)
array([[0, 3],
[2, 2]])
>>> x = np.array([3, 1, 2])
>>> np.argsort(x)
array([1, 2, 0])
def g(seq):
# http://stackoverflow.com/questions/3382352/equivalent-of-numpy-argsort-in-basic-python/3383106#3383106
#lambda version by Tony Veijalainen
return [x for x,y in sorted(enumerate(seq), key = lambda x: x[1])]