Search
 
SCRIPT & CODE EXAMPLE
 

PYTHON

df concat

pd.concat([s1, s2], ignore_index=True)
Comment

pandas concatenate

df1 = pd.DataFrame({"A": ["A0", "A1", "A2", "A3"]
                    , "B": ["B0", "B1", "B2", "B3"]
                    , "C": ["C0", "C1", "C2", "C3"]
                    , "D": ["D0", "D1", "D2", "D3"]
                    , "E": ['E0', 'E1', 'E2', 'E3']})
# since E0 isn't column in subsequent dfs their values will be NaN                  
df2 = pd.DataFrame({"A": ["A4", "A5", "A6", "A7"]
                    , "B": ["B4", "B5", "B6", "B7"]
                    , "C": ["C4", "C5", "C6", "C7"]
                    , "D": ["D4", "D5", "D6", "D7"]})
df3 = pd.DataFrame( {"A": ["A8", "A9", "A10", "A11"]
                     , "B": ["B8", "B9", "B10", "B11"]
                     , "C": ["C8", "C9", "C10", "C11"]
                    , "D": ["D8", "D9", "D10", "D11"]})
frames = [df1, df2, df3]
result = pd.concat(frames, ignore_index =True)#ignore index resets indecies
result #->

A	B	C	D	E
0	A0	B0	C0	D0	E0
1	A1	B1	C1	D1	E1
2	A2	B2	C2	D2	E2
3	A3	B3	C3	D3	E3
4	A4	B4	C4	D4	NaN
5	A5	B5	C5	D5	NaN
6	A6	B6	C6	D6	NaN
7	A7	B7	C7	D7	NaN
8	A8	B8	C8	D8	NaN
9	A9	B9	C9	D9	NaN
10	A10	B10	C10	D10	NaN
11	A11	B11	C11	D11	NaN
Comment

concatenate dataframes

# Stack the DataFrames on top of each other
#survey_sub and survey_sub_last10 are both dataframes
vertical_stack = pd.concat([survey_sub, survey_sub_last10], axis=0)

# Place the DataFrames side by side
horizontal_stack = pd.concat([survey_sub, survey_sub_last10], axis=1)
Comment

concat dataframes

result = pd.concat([df1, df2])
Comment

pandas concat

pd.concat(objs, axis=0, join='outer', join_axes=None, ignore_index=False,
       keys=None, levels=None, names=None, verify_integrity=False)

result = pd.concat([df1, df4], axis=1)
result = pd.concat(frames, keys=['x', 'y', 'z'])
result = pd.concat([df1, df4], axis=1, join='inner')
result = pd.concat([df1, df4], axis=1, join_axes=[df1.index])
Comment

concat dataframe pandas

# provide list of dataframes 
res = pd.concat([df1, df2])
Comment

pd.concat in python

s1 = pd.Series(['a', 'b'])
s2 = pd.Series(['c', 'd'])
pd.concat([s1, s2])

#GIVEN THAT BOTH HAS SAME INDEX
Comment

dataframe concatenate

# Pandas for Python

df['col1 & col2'] = df['col1']+df['col2']

#Output
#col1	col2	col1 & col2
#A1		A2		A1A2
#B1		B2		B1B2
Comment

pd df concat

pd.concat([pd.DataFrame([i], columns=['A']) for i in range(5)],
...           ignore_index=True)
Comment

PREVIOUS NEXT
Code Example
Python :: python how to open a file in a different directory in mac 
Python :: dropping nan in pandas dataframe 
Python :: del keyword in python 
Python :: import matplotlib plt 
Python :: primary key django model 
Python :: django post request 403 forbidden 
Python :: how to change role permissions in discord.py 
Python :: py how to deactivate venv 
Python :: python read html table 
Python :: pyqt loading screen 
Python :: variable naming rule in python 
Python :: generics python 
Python :: Concat and Append DFs Python 
Python :: parquet to dataframe 
Python :: os.listdir in python 
Python :: sqlite3 python parameterized query 
Python :: python turn true or false into 0 or 1 
Python :: bar labeling in matplotlib 
Python :: save dictionary to file numpy 
Python :: python remove new line 
Python :: pyodbc sql save pandas dataframe 
Python :: how to check django rest framework version 
Python :: binary to decimal in python 
Python :: selenium get parent element python 
Python :: python randomize a dataframe pandas 
Python :: how to enable execution time in jupyter lab 
Python :: ternary operator python 
Python :: Insert missing data in pandas 
Python :: set cookie in chrome 
Python :: virtual enviroment 
ADD CONTENT
Topic
Content
Source link
Name
2+6 =