how to print palindrome in 100 between 250 in python
>>> def isPalindrome(s):
''' check if a number is a Palindrome '''
s = str(s)
return s == s[::-1]
>>> def generate_palindrome(minx,maxx):
''' return a list of Palindrome number in a given range '''
tmpList = []
for i in range(minx,maxx+1):
if isPalindrome(i):
tmpList.append(i)
return tmpList
>>> generate_palindrome(1,120)
[1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111]
a=input('enter a string :')# palindrome in string
b=a[::-1]
if a==b:
print(a,'is a palindrome')
else:
print(a,'is not a palindrome')
print('a is not equal to b')
if a!=b:
print(b, 'the reverse of', a)
#output:
--------------------------------------------------------------------------------
case-I
# not palindrome
enter a string :1254
1254 is not a palindrome
a is not equal to b
4521 the reverse of 1254
--------------------------------------------------------------------------------
case-II
# palindrme
enter a string :12321
12321 is a palindrome
num=int(input("Enter a no.:"))
rev=0
num1=num
while num!=0:
rev=rev*10+(num%10)
num=num//10
if num1==rev:
print(num1," is a palindrome")
else:
print(num1," is not a palindrome")
n = input("Enter the word and see if it is palindrome: ") #check palindrome
if n == n[::-1]:
print("This word is palindrome")
else:
print("This word is not palindrome")
print("franco")
Python Program to Check if binary representation is a palindrome
# Function to check if binary representation of
# a number is palindrome or not
def binarypalindrome(num):
# convert number into binary
binary = bin(num)
# skip first two characters of string
# because bin function appends '0b' as
# prefix in binary representation of
# a number
binary = binary[2:]
# now reverse binary string and compare
# it with original
return binary == binary[-1::-1]
# Driver program
if __name__ == "__main__":
num = 9
print binarypalindrome(num)
How to check if a given string is a palindrome, in Python?
"""
This implementation checks whether a given
string is a palindrome. A string is
considered to be a palindrome if it reads the
same forward and backward. For example, "kayak"
is a palindrome, while, "door" is not.
Let n be the length of the string
Time complexity: O(n),
Space complexity: O(1)
"""
def isPalindrome(string):
# Maintain left and right pointers
leftIdx = 0
rightIdx = len(string)-1
while leftIdx < rightIdx:
# If chars on either end don't match
# string cannot be a palindrome
if string[leftIdx] != string[rightIdx]:
return False
# Otherwise, proceed to next chars
leftIdx += 1
rightIdx -= 1
return True
print(isPalindrome("kayak")) # True
print(isPalindrome("door")) # False
myString = "aba"
if myString == myString[::-1]:
print("The string '" + myString + "' is a palindrome")
else:
print("The string '" + myString + "' is not a palindrome")
string = input("Type a string: ")
if string[::-1] == string:
print(string,"This string is Palindrome")
else:
print(string,"This string is not Palindrome")
value = input("Enter a Word: ")
if value == value[::-1] :
print(value)
print(value[::-1])
print("THIS WORD IS A PALINDROME")
else :
print(value)
print(value[::-1])
print("THIS WORD IS NOT A PALINDROME")
mes=input("Enter the word and see if it is palindrome ")
if mes==mes[::-1]:
print("This word is palindrome")
else:
print("This word is not palindrome")
# Python3 code to demonstrate
# checking a number is palindrome
# using str() + string slicing
# initializing number
test_number = 9669669
# printing the original number
print ("The original number is : " + str(test_number))
# using str() + string slicing
# for checking a number is palindrome
res = str(test_number) == str(test_number)[::-1]
# printing result
print ("Is the number palindrome ? : " + str(res))
# Python3 code to demonstrate
# checking a number is palindrome
# using math.log() + recursion + list comprehension
import math
# the recursive function to reverse
def rev(num):
return int(num != 0) and ((num % 10) *
(10**int(math.log(num, 10))) +
rev(num // 10))
# initializing number
test_number = 9669669
# printing the original number
print ("The original number is : " + str(test_number))
# using math.log() + recursion + list comprehension
# for checking a number is palindrome
res = test_number == rev(test_number)
# printing result
print ("Is the number palindrome ? : " + str(res))
# Recursive function to check if a
# string is palindrome
def isPalindrome(s):
# to change it the string is similar case
s = s.lower()
# length of s
l = len(s)
# if length is less than 2
if l < 2:
return True
# If s[0] and s[l-1] are equal
elif s[0] == s[l - 1]:
# Call is palindrome form substring(1,l-1)
return isPalindrome(s[1: l - 1])
else:
return False
# Driver Code
s = "MalaYaLam"
ans = isPalindrome(s)
if ans:
print("Yes")
else:
print("No")
def is_palindrome(input_string):
# Create two strings, to compare them
new_string = ""
reverse_string = ""
# Traverse through each letter of the input string
for x in range(len(input_string)):
# This will give x the value of all the possible index numbers for each iteration
# Add any non-blank letters to the
# end of one string, and to the front
# of the other string.
if input_string[x] != " ":
new_string += input_string[x]
reverse_string = new_string[::-1]
# Compare the strings
if new_string.lower() == reverse_string.lower():
return True
return False
print(is_palindrome("Never Odd or Even")) # Should be True