PYTHON

python delete key from dict

del dictionary['key']

python remove key from dict

my_dict.pop('key', None)

remove element from dictionary python

thisdict = {
  "brand": "Ford",
  "model": "Mustang",
  "year": 1964
}
thisdict.pop("model")

python delete value from dictionary

dict.pop('key')

#optionally you can give value to return if key doesn't exist (default is None)
dict.pop('key', 'key not found')

delete an element from a dict python

del d[key]

python delete value from dictionary

dict = {'an':30, 'example':18}
#1 Del
del dict['an']

#2 Pop (returns the value deleted, but can also be used alone)
#You can optionally set a default return value in case key is not found
dict.pop('example') #deletes example and returns 18
dict.pop('test', 'Key not found') #returns 'Key not found'

delete key value in dictionary python

del d[key]  # no returns
d.pop(key)  # this returns value

remove element from dictionary python

dict.pop("key")

how to remove dictionary entry in python

del dic[key]

python dictionary delete by value

myDict = {key:val for key, val in myDict.items() if val != deletevalue}

python delete from dictionary

my_dict = {31: 'a', 21: 'b', 14: 'c'}

del my_dict[31]

print(my_dict)

how to remove an element from dictionary using his value python

a_dictionary = {"one": 1, "two" : 2, "three": 3}

desired_value = 2
for key, value in a_dictionary.items():
  if value == desired_value:
    del a_dictionary[key]
    break

print(a_dictionary)
--------------------------------------------------------------------------------
OUTPUT
{'one': 1, 'three': 3}

python dictionary delete based on value

# empty dictionary
dictionary = {}
# lists
list_1 = [1, 2, 3, 4, 5]
list_2 = ["a", "b", "c", "d", "e"]
# populate a dictionary.
for key, value in zip(list_1, list_2):
    dictionary[key] = value
# output
print(dictionary)

# Item to delete
item_1 = "c"

# Delete item from dictionary - based on values specified
for key, value in dictionary.items():
    if value == item_1:
        dictionary.pop(key)
        break

print(dictionary)

Dictionary Delete a Entry

hh = {"a":3, "b":4, "c":5}

# delete a entry
del hh["b"]
print(hh)
# {'a': 3, 'c': 5}

remove elements from dictionary python

squares = {1: 1, 2: 4, 3: 9, 4: 16, 5: 25}

# remove a particular item, returns its value
# Output: 16
print(squares.pop(4))

remove item dict py

dict.pop('key')

python remove dict key/values

# The pop() method can accept either one or two parameters:
# The name of the key you want to remove (mandatory).
# The value that should be returned if a key cannot be found (optional).
dictionary.pop(key_to_remove, not_found)

remove item in dict

def removekey(d, key):
    r = dict(d)
    del r[key]
    return r

remove dict python

del r[key]

python delete key from dict

del dictionary['key']

python remove key from dict

my_dict.pop('key', None)

remove element from dictionary python

thisdict = {
  "brand": "Ford",
  "model": "Mustang",
  "year": 1964
}
thisdict.pop("model")

python delete value from dictionary

dict.pop('key')

#optionally you can give value to return if key doesn't exist (default is None)
dict.pop('key', 'key not found')

delete an element from a dict python

del d[key]

python delete value from dictionary

dict = {'an':30, 'example':18}
#1 Del
del dict['an']

#2 Pop (returns the value deleted, but can also be used alone)
#You can optionally set a default return value in case key is not found
dict.pop('example') #deletes example and returns 18
dict.pop('test', 'Key not found') #returns 'Key not found'

delete key value in dictionary python

del d[key]  # no returns
d.pop(key)  # this returns value

remove element from dictionary python

dict.pop("key")

how to remove dictionary entry in python

del dic[key]

python dictionary delete by value

myDict = {key:val for key, val in myDict.items() if val != deletevalue}

python delete from dictionary

my_dict = {31: 'a', 21: 'b', 14: 'c'}

del my_dict[31]

print(my_dict)

how to remove an element from dictionary using his value python

a_dictionary = {"one": 1, "two" : 2, "three": 3}

desired_value = 2
for key, value in a_dictionary.items():
  if value == desired_value:
    del a_dictionary[key]
    break

print(a_dictionary)
--------------------------------------------------------------------------------
OUTPUT
{'one': 1, 'three': 3}

python dictionary delete based on value

# empty dictionary
dictionary = {}
# lists
list_1 = [1, 2, 3, 4, 5]
list_2 = ["a", "b", "c", "d", "e"]
# populate a dictionary.
for key, value in zip(list_1, list_2):
    dictionary[key] = value
# output
print(dictionary)

# Item to delete
item_1 = "c"

# Delete item from dictionary - based on values specified
for key, value in dictionary.items():
    if value == item_1:
        dictionary.pop(key)
        break

print(dictionary)

Dictionary Delete a Entry

hh = {"a":3, "b":4, "c":5}

# delete a entry
del hh["b"]
print(hh)
# {'a': 3, 'c': 5}

remove elements from dictionary python

squares = {1: 1, 2: 4, 3: 9, 4: 16, 5: 25}

# remove a particular item, returns its value
# Output: 16
print(squares.pop(4))

remove item dict py

dict.pop('key')

python remove dict key/values

# The pop() method can accept either one or two parameters:
# The name of the key you want to remove (mandatory).
# The value that should be returned if a key cannot be found (optional).
dictionary.pop(key_to_remove, not_found)

remove item in dict

def removekey(d, key):
    r = dict(d)
    del r[key]
    return r

remove dict python

del r[key]