s = {0, 1, 2}
s.discard(0)
print(s)
{1, 2}
# discard() does not throw an exception if element not found
s.discard(0)
# remove() will throw
s.remove(0)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
KeyError: 0
# Creating an empty set
b = set()
print(type(b))
## Adding values to an empty set
b.add(4)
b.add(4)
b.add(5)
b.add(5) # Adding a value repeatedly does not changes a set
b.add((4, 5, 6))
## Accessing Elements
# b.add({4:5}) # Cannot add list or dictionary to sets
print(b)
## Length of the Set
print(len(b)) # Prints the length of this set
## Removal of an Item
b.remove(5) # Removes 5 fromt set b
How To Remove Elements From a Set using discard() function in python
# discard() function will not raise an error if the given value to remove
# does not exist within the set
mySet = {1, 2, 3}
mySet.discard(1)
print(mySet)
# Output:
# {2, 3}