PYTHON

how many three-digit multiples of 18 have the sum of the digits also equal 18?

//I coded this question in python here is how i got the ans 25:

from numpy import integer
count=0
finalcount=0

for i in range (100,999):
    if i/18 == int(i/18):
        count= count + 1
        n=i
        if sum([int(d) for d in str(n)])==18:
            finalcount= finalcount + 1

print(finalcount)
// answer is 25

Sum of all the multiples of 3 or 5

const findSum = n => {
  let countArr = []
  
  for(let i = 0; i <= n; i++) if(i % 3 === 0 || i % 5 === 0) countArr.push(i) 
  return countArr.reduce((acc , curr) => acc + curr)
}
console.log(findSum(5))

// With love @kouqhar

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000.

total_sum = 0
for i in range(1000):
    if (i%3 == 0 or i%5 == 0):
        total_sum = total_sum+i
print total_sum