PYTHON

intersection in list

def intersection(lst1, lst2): 
    lst3 = [value for value in lst1 if value in lst2] 
    return lst3 
  
# Driver Code 
lst1 = [4, 9, 1, 17, 11, 26, 28, 54, 69] 
lst2 = [9, 9, 74, 21, 45, 11, 63, 28, 26] 
print(intersection(lst1, lst2)) 

intersection of lists in python

import numpy as np
recent_coding_books =  np.intersect1d(recent_books,coding_books)

python list intersection

# intersection of two lists (lst1 & lst2)
In [1]: x = ["a", "b", "c", "d", "e"]

In [2]: y = ["f", "g", "h", "c", "d"]

In [3]: set(x).intersection(y)
Out[3]: {'c', 'd'}
# has_intersection = bool(set(x).intersection(y)) -> True

python list INTERSECTION

a = ['apple', 'banana', 'pear']
b = ['fridge', 'stove', 'banana']

a & b == ['banana'] #True

intersection of list of sets

u = set.intersection(*setlist)