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is prime python

def is_prime(n):
    for i in range(2,int(n**0.5)+1):
        if n%i==0:
            return False
    return True
Comment

is prime python

import math
def isPrimeNumber(n):
    if (n < 2):
        return False;
    sq = int(math.sqrt(n))
    for i in range(2, sq + 1):
        if (n % i == 0):
            return False
    return True
Comment

primes in python

from math import sqrt
for i in range(2, int(sqrt(num)) + 1):
    if num % i == 0:
        print("Not Prime")
        break
    print("Prime")

# Note: Use this if your num is big (ex. 10000 or bigger) for efficiency
# The result is still the same if the num is smaller
Comment

primes pytyhon

def is_prime(n):
    if n in (2, 3):
        return True
    if n <= 1 or not (n%6==1 or n%6==5):
        return False
    a, b= 5, 2
    while a <= n**0.5:
        if not n%a:
            return False
        a, b = a+b, 6-b
    return True
# this method is much faster than checking every number because it uses the fact
# that every prime is either 1 above or 1 below a multiple of 6
# and that if a number has no prime factors, it has no factors at all
Comment

python is prime

from sympy import isprime
isprime(23)
Comment

python primes

def is_prime(n):
  for i in range(2,n):
    if (n%i) == 0:
      return False
  return True
Comment

check for prime in python

def is_prime(n: int) -> bool:
    """Primality test using 6k+-1 optimization."""
    import math
    if n <= 3:
        return n > 1
    if n % 2 == 0 or n % 3 == 0:
        return False
    i = 5
    while i <= math.sqrt(n):
        if n % i == 0 or n % (i + 2) == 0:
            return False
        i += 6
    return True
Comment

python is prime

from math import sqrt, floor;

def is_prime(num):
    if num < 2: return False;
    if num == 2: return True;
    if num % 2 == 0: return False;
    for i in range(3,floor(sqrt(num))+1,2):
        if num % i == 0: return False;
    return True;
Comment

primes python

import math

def main():
    count = 3
    
    while True:
        isprime = True
        
        for x in range(2, int(math.sqrt(count) + 1)):
            if count % x == 0: 
                isprime = False
                break
        
        if isprime:
            print count
        
        count += 1
Comment

is prime python

def is_prime(n):
  return bool(n&1)
Comment

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