PYTHON

python find the key with max value

a_dictionary = {"a": 1, "b": 2, "c": 3}

# get key with max value
max_key = max(a_dictionary, key=a_dictionary.get)

print(max_key)

python get the key with the max or min value in a dictionary

# Basic syntax:
key_with_max_value = max(dictionary, key=dictionary.get)

# Note, to get the max value itself, you can do either of the following:
max_value = dictionary[max(dictionary, key=dictionary.get)]
max_value = max(dictionary.values())

# Example usage:
dictionary = {"a": 1, "b": 2, "c": 3}
max(dictionary, key=dictionary.get)
--> 'c'

find the max value in dictionary python

my_dict = {'a': 5, 'b': 10, 'c': 6, 'd': 12, 'e': 7}
max(my_dict, key=my_dict.get) # returns 'd'

python max key dictionary key getter

from operator import itemgetter

items = [
    {'a': 1, 'b': 99},
    {'a': 2, 'b': 88},
    {'a': 3, 'b': 77},
]

print(max(items, key=itemgetter('a')))
print(max(items, key=itemgetter('b')))

get max n values in dict py

import heapq
from operator import itemgetter

n = 3

items = {'a': 7, 'b': 12, 'c': 9, 'd': 0, 'e': 24, 'f': 10, 'g': 24}

topitems = heapq.nlargest(n, items.items(), key=itemgetter(1))  # Use .iteritems() on Py2
topitemsasdict = dict(topitems)