# Python code to iterate over a listlist=[1,2,3,4,5,6]# Method 1: Using "var_name in list" syntax# Pro: Consise, easily readable# Con: Can't access index of itemfor item inlist:print(item)# Method 2: Using list indices# Pro: Can access index of item in list# Con: Less consise, more complicated to readfor index inrange(len(list)-1):print(list[index])# Method 3: Using enumerate()# Pro: Can easily access index of item in list# Con: May be too verbose for some codersfor index, value inenumerate(list):print(value)
#if you want iterate the list one by one you can simply use for loop
list1 =[1,True,"Meerab",8.9]for i in list1:print(i)#if you want to iterate the list along with an index number#The index value starts from 0 to (length of the list-1)
list2 =[3,9,"Ahmed",2.98,"Tom"]#To find the len of list we can builtin function len()
size =len(list2)#iterate a listfor j inrange(1,size):#you can give a range that you want to iterate# print each item using index numberprint(list2[i])
# a 'while' loop runs until the condition is broken
a ="apple"while a =="apple":
a ="banana"# breaks loop as 'a' no longer equals 'apple'# a 'for' loop runs for the given number of iterations...for i inrange(10):print(i)# will print 0, 1, 2, 3, 4, 5, 6, 7, 8, 9# ... or through a sequence
array =[3,6,8,2,1]for number in array:print(number)# will print 3, 6, 8, 2, 1
import itertools
list_1 =[1,2,3,4]
list_2 =['a','b','c']# loop until the short loop stopsfor i,j inzip(list_1,list_2):print(i,j)print("
")# loop until the longer list stopsfor i,j in itertools.zip_longest(list_1,list_2):print(i,j)