PYTHON

python sort a dictionary by values

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}

sort_by_key = dict(sorted(x.items(),key=lambda item:item[0]))
sort_by_value = dict(sorted(x.items(), key=lambda item: item[1]))

print("sort_by_key:", sort_by_key)
print("sort_by_value:", sort_by_value)

# sort_by_key: {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
# sort_by_value: {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

sort list of dictionaries by key python

newlist = sorted(list_to_be_sorted, key=lambda k: k['name']) 

how to sort a dictionary by value in python

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))

how to sort values in python from dictionary to list

x = {'a':1, 'b':2, 'c':3, 'd':4, 'e':5}

accending_x_keys = sorted(x, key=x.get)
descending_x_keys = sorted(x, key=x.get, reverse=True)

for k in accending_x_keys:
    print(k, x.get(k), end=" ")
#output: a 1 b 2 c 3 d 4 e 5   
for v in descending_x_keys:
    print(v, x.get(v), end=" ")
#output: e 5 d 4 c 3 b 2 a 1

sort list of dictionaries python

unsorted_list = [{"key1":5, "key2":2}, {"key1":5, "key2":1}]
sorted_list = sorted(unsorted_list, key=lambda k: k["key2"])

how to sort dictionary in python by value

# your dictionary
a = {'a':4, 'c':5, 'b':3, 'd':0}

# sort x by keys
a_keys = dict(sorted(a.items(),key=lambda x:x[0],reverse = False)) # ascending order
# output: {'a': 4, 'b': 3, 'c': 5, 'd': 0}

# # sort x by values
a_values = dict(sorted(a.items(),key=lambda x:x[1],reverse = False)) # ascending order
# output: {'d': 0, 'b': 3, 'a': 4, 'c': 5}

sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

sort dict by value

dict(sorted(x.items(), key=lambda item: item[1]))

sort dict by value python 3

>>> d = {"aa": 3, "bb": 4, "cc": 2, "dd": 1}
>>> for k in sorted(d, key=d.get, reverse=True):
...     k, d[k]
...
('bb', 4)
('aa', 3)
('cc', 2)
('dd', 1)

how to sort list of dictionaries in python

rows = [
{'fname': 'Brian', 'lname': 'Jones', 'uid': 1003},
{'fname': 'David', 'lname': 'Beazley', 'uid': 1002},
{'fname': 'John', 'lname': 'Cleese', 'uid': 1001},
{'fname': 'Big', 'lname': 'Jones', 'uid': 1004}
]

from operator import itemgetter
rows_by_fname = sorted(rows, key= itemgetter('fname'))
rows_by_uid = sorted(rows, key=itemgetter('uid'))

sort dict by value

>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

python sort array of dictionary by value

my_list = sorted(my_list, key=lambda k: k['name'])

sort dictionary by value and then key python

sorted(y.items(), key=lambda x: (x[1],x[0]))

python sort the values in a dictionaryi

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

python sort dict by value

A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A, key=A.get)}

output:
{4: -20, 1: 2, -1: 4}

Sorting a List of Dictionaries

csv_mapping_list = [
  { "Name": "Jeremy", "Age": 25, "Favorite Color": "Blue" }, 
  { "Name": "Ally", "Age": 41, "Favorite Color": "Magenta" }, 
  { "Name": "Jasmine", "Age": 29, "Favorite Color": "Aqua" }
]

# Custom sorting
size = len(csv_mapping_list)
for i in range(size): 
  min_index = i 
  for j in range(i + 1, size): 
    if csv_mapping_list[min_index]["Age"] > csv_mapping_list[j]["Age"]: 
      min_index = j 
      csv_mapping_list[i], csv_mapping_list[min_index] = csv_mapping_list[min_index], csv_mapping_list[i]

# List sorting function
csv_mapping_list.sort(key=lambda item: item.get("Age"))

# List sorting using itemgetter
from operator import itemgetter
f = itemgetter('Name')
csv_mapping_list.sort(key=f)

# Iterable sorted function
csv_mapping_list = sorted(csv_mapping_list, key=lambda item: item.get("Age"))

how to sort dict by value

dict1 = {1: 1, 2: 9, 3: 4}
sorted_dict = {}
sorted_keys = sorted(dict1, key=dict1.get)  # [1, 3, 2]

for w in sorted_keys:
    sorted_dict[w] = dict1[w]

print(sorted_dict) # {1: 1, 3: 4, 2: 9}

sorting values in dictionary in python

#instead of using python inbuilt function we can it compute directly.
#here iam sorting the values in descending order..
d = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
s=[]
for i in d.items():
  s.append(i)
for i in range(0,len(s)):
  for j in range(i+1,len(s)):
    if s[i][1]<s[j][1]:
      s[i],s[j]=s[j],s[i]
print(dict(s))

python sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}

python sort dictionary by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}

sort_by_key = dict(sorted(x.items(),key=lambda item:item[0]))
sort_by_value = dict(sorted(x.items(), key=lambda item: item[1]))

print("sort_by_key:", sort_by_key)
print("sort_by_value:", sort_by_value)

# sort_by_key: {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
# sort_by_value: {0: 0, 2: 1, 1: 2, 4: 3, 3: 4

sort a dict by values

{k: v for k, v in sorted(dic.items(), key=lambda item: item[1])}

sort dict by values

>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

python Sort the dictionary based on values

dt = {5:4, 1:6, 6:3}

sorted_dt = {key: value for key, value in sorted(dt.items(), key=lambda item: item[1])}

print(sorted_dt)

sort dict by value

for w in sorted(d, key=d.get, reverse=True):
    print(w, d[w])

How to sort a Python dict by value

# How to sort a Python dict by value
# (== get a representation sorted by value)

>>> xs = {'a': 4, 'b': 3, 'c': 2, 'd': 1}

>>> sorted(xs.items(), key=lambda x: x[1])
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]

# Or:

>>> import operator
>>> sorted(xs.items(), key=operator.itemgetter(1))
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]

python Sort the dictionary based on values

dt = {5:4, 1:6, 6:3}

sorted_dt_value = sorted(dt.values())
print(sorted_dt_value)

sort dict by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}
a = sorted(d.items(), key=lambda x: x[1])    
print(a)

python order list of dictionaries by value

newlist = sorted(list_to_be_sorted, key=lambda d: d['name'])