R - Use regex to extract row in R (problem)

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Use regex to extract row in R (problem)

aName   bName   pName   call  alleles   logRatio    strength
AX-11086564 F08_ADN103  2011-02-10_R10  AB  CG  0.363371    10.184215
AX-11086564 A01_CD1919  2011-02-24_R11  BB  GG  -1.352707   9.54909
AX-11086564 B05_CD2920  2011-01-27_R6   AB  CG  -0.183802   9.766334
AX-11086564 D04_CD5950  2011-02-09_R9   AB  CG  0.162586    10.165051
AX-11086564 D07_CD6025  2011-02-10_R10  AB  CG  -0.397097   9.940238
AX-11086564 B05_CD3630  2011-02-02_R7   AA  CC  2.349906    9.153076
AX-11086564 D04_ADN103  2011-02-10_R2   BB  GG  -1.898088   9.872966
AX-11086564 A01_CD2588  2011-01-27_R5   BB  GG  -1.208094   9.239801

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Use regex to extract row in R (solution 1)

subset(dat, grepl("ADN", bName)  &  pName == "2011-02-10_R2" )

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Use regex to extract row in R (solution 2)

 dat[ with(dat,  grepl("ADN", bName)  &  pName == "2011-02-10_R2" ) , ]

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Use regex to extract row in R (problem)

Use regex to extract row in R (solution 1)

Use regex to extract row in R (solution 2)

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