SQL

write sql query to find the second highest salary of employee

SELECT MAX(Salary) From Employee
 WHERE Salary < ( SELECT Max(Salary) FROM Employee);

How to find third highest salary in SQL

-- creating Employee table in Oracle
CREATE TABLE Employee (name varchar(10), salary int);

-- inserting sample data into Employee table
INSERT INTO Employee VALUES ('Rick', 3000);
INSERT INTO Employee VALUES ('John', 4000);
INSERT INTO Employee VALUES ('Shane', 3000);
INSERT INTO Employee VALUES ('Peter', 5000);
INSERT INTO Employee VALUES ('Jackob', 7000);

SELECT TOP 1 salary 
FROM (
  SELECT DISTINCT TOP 3 salary FROM Employee ORDER BY salary DESC 
  ) AS temp 
ORDER BY salary

sql find second highest salary employee

/* sql 2nd highest salary employee */
select sal, ename
from emp
where sal =
    (
        select max(sal) from emp where sal <
            (select max(sal) from emp)
    )
----------------------------------------------- option 2
select *
from 
(
    select ename, sal, dense_rank() over(order by sal desc) rank
    from emp
)
where rank =2;

query to find third highest salary

-*FOR THIRD HIGHEST SALARY*

Select top 1 from (select top 3 salary from emp order by salary desc)
order by asc

sql highest salary by location

/*  Highest salary by Department/Location   */
SELECT e.ename, e.sal, e.deptno, d.loc
FROM emp e
JOIN dept d
ON e.deptno = d.deptno
WHERE e.sal in
( 	
  	select max(sal) 
  	from emp 
  	group by deptno
)

how to get second highest salary in each department in sql

SELECT E.Employers_name, E.dep_number, E.salary
FROM Employers E
WHERE 1 = (SELECT COUNT(DISTINCT salary) 
        FROM Employers B 
        WHERE B.salary > E.salary AND E.dep_number = B.dep_number)
group by E.dep_number