// The following implementation assumes that the activities
// are already sorted according to their finish time
import java.util.*;
import java.lang.*;
import java.io.*;
class ActivitySelection
{
// Prints a maximum set of activities that can be done by a single
// person, one at a time.
// n --> Total number of activities
// s[] --> An array that contains start time of all activities
// f[] --> An array that contains finish time of all activities
public static void printMaxActivities(int s[], int f[], int n)
{
int i, j;
System.out.print("Following activities are selected : n");
// The first activity always gets selected
i = 0;
System.out.print(i+" ");
// Consider rest of the activities
for (j = 1; j < n; j++)
{
// If this activity has start time greater than or
// equal to the finish time of previously selected
// activity, then select it
if (s[j] >= f[i])
{
System.out.print(j+" ");
i = j;
}
}
}
// driver program to test above function
public static void main(String[] args)
{
int s[] = {1, 3, 0, 5, 8, 5};
int f[] = {2, 4, 6, 7, 9, 9};
int n = s.length;
printMaxActivities(s, f, n);
}
}