# Program to check the list contains elements of another list# List1
List1 =['python' , 'javascript', 'csharp', 'go','c', 'c++']# List2
List2 =['csharp1' , 'go', 'python']
check =all(item in List1 for item in List2)if check isTrue:print("The list {} contains all elements of the list {}".format(List1, List2))else:print("No, List1 doesn't have all elements of the List2.")
check if a list contains any item from another list python
## using set
list_A =[1,2,3,4]
list_B =[2,3]
set_A =set(list_A)
set_B =set(list_B)print(set_A.intersection(set_B))# True if there is any element same# False if there is no element same
'''
check if list1 contains any elements of list2
'''
result =any(elem in list1 for elem in list2)if result:print("Yes, list1 contains any elements of list2")else:print("No, list1 contains any elements of list2")
how to check if a list contains elements in another list
##Taking examples of two python lists.##Take examples of two lists.
list1 =[2,4,0,7,6]
list2 =[1,0,9,7,6]##the statement for condition is.
check =any(element in list2 for element in list1)
check if a list contains any item from another list python
## using set
list_A =[1,2,3,4]
list_B =[5,1]
set_A =set(list_A)
set_B =set(list_B)
output = False if(set_A.intersection(set_B)==set())elseTrueprint(output)# True if there is any element same# False if there is no element same
Python check if all elements exist in another list
fruits1 =['Mango','orange','apple','jackfruit']
fruits2 =['Mango','orange','apple','jackfruit']
new_list=all(item in fruits1 for item in fruits2)if new_list isTrue:print("True")else:print("False")
// You could use a nested Any() for this check which is available on any Enumerable:bool hasMatch = myStrings.Any(x => parameters.Any(y => y.source == x));// Faster performing on larger collections would be to project parameters to source and// then use Intersect which internally uses a HashSet<T> so instead of O(n^2) for the// first approach (the equivalent of two nested loops) you can do the check in O(n) :bool hasMatch = parameters.Select(x => x.source).Intersect(myStrings).Any();// source: https://stackoverflow.com/a/11092955