constresult=(data)=>{let max =0;for(let i =0; i < data.length; i++){if(data[i]> max){
max = data[i];}}console.log("===> :: max", max);}const inputData =[2,3,5,4,54,69,4,44,3,6,45,6,4,6]result(inputData);
functionfindHighestNumber(nums){let inputs = nums.filter((val, i)=> nums.indexOf(val)=== i)let max =Math.max(...nums);let min =Math.min(...nums);return max +(-min);}console.log(difference([1,7,18,-1,-2,9]));
Find largest number from array by function in javascript
functionlargestElements(numbers){var largest =0;for(let i =0; i < numbers.length; i++){var elements = numbers[i];if(elements > largest){
largest = elements;}}return largest;}const numbers =[2,3,4,8,5,2,4];console.log(largestElements(numbers));//Output: 8
var myPersons__ =document.querySelectorAll('.avtrlnk');var maxId__ =[];for(var x =0; x < myPersons__.length;++x){
maxId__[x]= myPersons__[x].value;}
myPersons__ =parseInt(maxId__.sort()[x-1])+1;
find the largest array from an array in javascript
const numbers =[[1,2,3],[4,5,6],[7,8,9,10,11],];let largestArray = numbers[0].length;for(let i =1; i < numbers.length; i++){if(numbers[i].length> largestArray){
largestArray = numbers[i];for(let j =0; j < largestArray.length; j++){console.log(numbers[i][j]);}}}//it will print 7, 8, 9, 10, 11 as these numbers are in largest array;
constfindMax=(arr)=>{let max =0;for(let index =0; index < arr.length; index++){if(max < arr[index]&& max != arr[index]){
max = arr[index];}}return max;}//if you find this answer is useful ,//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)