Search
 
SCRIPT & CODE EXAMPLE
 

PYTHON

append to a ldictionary value list

#list.append returns None, since it is an in-place operation and you are 
#assigning it back to dic[key]. So, the next time when you do 
#dic.get(key, []).append you are actually doing None.append. 
#That is why it is failing. Instead, you can simply do
dates_dict.setdefault(key, []).append(date)
#or 
from collections import defaultdict
dates_dict = defaultdict(list)
for key, date in cur:
    dates_dict[key].append(date)
Comment

PREVIOUS NEXT
Code Example
Python :: Requests-html absolute url 
Python :: Introduction to distutils in python 
Python :: python lvl up 
Python :: django domain name 
Python :: find the middle of the document in the image opencv 
Python :: Python:Gann square of 9 
Python :: convert integer to binary python 
Python :: python open multiple .py windows 
Python :: wand image resize 
Python :: python format method align center 
Python :: how to get coupons from honey in python 
Python :: Python downsampling 
Python :: using rlike in pyspark for numeric 
Python :: how to import autpy 
Python :: python -c crypt command in python3.3 and above 
Python :: flask files not updating 
Python :: how to send variable to python using xlwings 
Python :: get current worker id multiprocessing 
Python :: django time cualtulate 
Python :: delete row by index pandas 
Python :: run exe for python and wait until finish 
Python :: ignore transformers warning 
Python :: Matplotlib giving error "OverflowError: In draw_path: Exceeded cell block limit" 
Python :: pandas convert text duration to minutes 
Python :: abrir notebooks jupyter administrador de archivos 
Python :: text to qr code python 
Python :: queryset.raw() in django rest framework joining tables 
Python :: pyqt5 udp example 
Python :: max sum slice python 5 - autopilot 
Python :: pyspark pivot max aggregation 
ADD CONTENT
Topic
Content
Source link
Name
1+8 =