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python binary representation of numbers

# get integer version of binary number
int(bin(8)[2:])
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binary representation python

>>> bin(88)
'0b1011000'
>>> int('0b1011000', 2)
88
>>> 

>>> a=int('01100000', 2)
>>> b=int('00100110', 2)
>>> bin(a & b)
'0b100000'
>>> bin(a | b)
'0b1100110'
>>> bin(a ^ b)
'0b1000110'
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generate binary number in python

num = int(input("Enter a number: ")) #generates a number
print(int(bin(num[2:]))) #converts the number to binary and prints it
#the [2:] is there because there is a b showing it is bnary but we dont want that in a binary number
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binary python

def bin(n):
    s=""
    while n!=0:
        if n%2==1:
            s+="1"
            n//=2
        elif n%2==0:
            s+='0'
            n//=2
    return s
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