PYTHON

value count a list python

from collections import Counter
z = ['blue', 'red', 'blue', 'yellow', 'blue', 'red']
Counter(z)
>>> Counter({'blue': 3, 'red': 2, 'yellow': 1})

count items in list

>>> from collections import Counter
>>> mylist = ["Bob", "Mike", "Bob", "Mike", "Mike", "Mike", "Bob"]
>>> Counter(mylist)
Counter({'Mike': 4, 'Bob': 3})

count the element in list

from collections import Counter
 
thelist = [1, 4, 2, 3, 5, 4, 5, 6, 7, 8, 1, 3, 4, 5, 9, 10, 11]
c = Counter(thelist)
print(c.most_common(1))

count item in list python

list.count(element)

python count items in list

from collections import Counter
a = [1,2,3,4,5,6,6,6,5,5]
Counter(a)

count number items in list python

mylist = ["abc", "def", "ghi", "jkl", "mno", "pqr"]

print(len(mylist))

# output 6

Count elements in list Python

List = ["Elephant", "Snake", "Penguin"]

print(len(List))

#	With the 'len' function Python counts the amount of elements 
#	in a list (The length of the list).

count number of element in list

"""Find all occurrences of element in list"""

# If you simply want find how many times an element appears
# use the built-in function count()
def find_occur(lst, item):
	return lst.count(item)

# Test -----------------------------------------------------------
print(find_occur([None, None, 1, 2, 3, 4, 5], None)) # 2

# If you wanna find where they occur instead
# - This returns the indices where element is found within a list

def find(lst, item):
    return [i for (i, x) in enumerate(lst) if x == item]

# Test Code ------------------------------------------------------
from random import randint, choice
lst = [randint(0, 99) for x in range(10)] # random lst
item = choice(lst) # item to find
found = find(lst, item) # lst of where item is found at
print(f"lst: {lst}",
      f"item: {item}",
      f"found: {found}",
      sep = "
")

List Count Elements

a = ["more", 4, 6]
print(len(a))
# prints 3