PYTHON

program to find even numbers in python

m = int(input("Enter number"))
if m % 2 == 0:
    print(m,"is an even number")
else:
    print(m,"is an odd number")

    

how to detect an even number in python

mynumber = int(input("Enter number")) # Ask an integer number to the user
if mynumber % 2 == 0: # % = modelo, It is equal to the rest of the division
  print(mynumber, "is an even number")
else: # The rest of 7 / 2 is 2.5, not 0
  print(mynumber, "is an odd number")

Even numbers in Python

count1 = 0
for even_number in range(1, 20):
    if even_number % 2 == 0:
        count1 += 1
        print(even_number)
print(f"we have {count1} even numbers")

odd number in python

for tc in range(int(input())):
    a,b = map(int,input().split())
    x =  b//2 + (b%2)
    y =  a//2
    print("Case %d: %d"%(tc+1,x*x-y*y))
    
"""
Input:
2
1 10
2 10
Output:
Case 1: 25
Case 2: 24
"""