PYTHON

how to find the calendar week python

import datetime
my_date = datetime.date.today() # if date is 01/01/2018
year, week_num, day_of_week = my_date.isocalendar()
print("Week #" + str(week_num) + " of year " + str(year))

#OUTPUT
#Week #1 of year 2018

get current week python

import datetime
my_date = datetime.date.today() # if date is 01/01/2018
year, week_num, day_of_week = my_date.isocalendar()
print("Week #" + str(week_num) + " of year " + str(year))

python get date next week

import datetime

today = datetime.date.today()

next_week = today + datetime.timedelta(days=7)

get weekday from date python

>>> import datetime
>>> datetime.datetime.today()
datetime.datetime(2012, 3, 23, 23, 24, 55, 173504)
>>> datetime.datetime.today().weekday()
4

Python Day of the week

>>> from datetime import datetime
>>> datetime.today().strftime('%A')
'Wednesday'

how to get today weekday in python

today_day = date.today()
days = ["Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","sunday"]
print("Today weekday is ",days[today_day.weekday()])

get week from datetime python

import datetime as dt
dt.datetime.strptime('2019-01-01', '%Y-%m-%d').isocalendar()[1]

python datetime get date one week from today

>>> import datetime
>>> datetime.datetime.now() + datetime.timedelta(days=7)

get weekday from date python

# int value range: 0-6, monday-sunday
weekday = datetime.weekday()

How to get the date from week number in Python?

import datetime
from dateutil.relativedelta import relativedelta
 
week = 25
year = 2021
date = datetime.date(year, 1, 1) + relativedelta(weeks=+week)
print(date)