PYTHON

count how many vowels in a string python

def vowel_count(string):
  vowels = ['a', 'e', 'i', 'o', 'u']
  return len([i for i in string if i in vowels])

python program to count vowels in a string

whatever=input("Enter something
")
vowels = ['a', 'e', 'i', 'o', 'u']
vowelp = ([i for i in whatever if i in vowels])
vowelcount = len([i for i in whatever if i in vowels])
print ("there are", vowelcount, "vowels (y is not counted)")
print ("the vowels are:", vowelp)

python count the vowels

# Using dictionary and list comprehension

ip_str = 'Hello, have you tried our tutorial section yet?'

# make it suitable for caseless comparisions
ip_str = ip_str.casefold()

# count the vowels
count = {x:sum([1 for char in ip_str if char == x]) for x in 'aeiou'}

print(count)

python count the vowels

# Program to count the number of each vowels

# string of vowels
vowels = 'aeiou'

ip_str = 'Hello, have you tried our tutorial section yet?'

# make it suitable for caseless comparisions
ip_str = ip_str.casefold()

# make a dictionary with each vowel a key and value 0
count = {}.fromkeys(vowels,0)

# count the vowels
for char in ip_str:
   if char in count:
       count[char] += 1

print(count)