PYTHON

dictionary sort python

d={
  3: 4,
  1: 1,
  0: 0,
  4: 3,
  2: 1
}
y=dict(sorted(d.items(), key=lambda item: item[1]))
print(y) # {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

sort dictionary python

l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

sort dictionary

#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples

sort the dictionary in python

d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

python dictionary sort

# empty dictionary
dictionary = {}
# lists
list_1 = [1, 2, 3, 4, 5]
list_2 = ["e", "d", "c", "b", "a"]
# populate a dictionary.
for key, value in zip(list_1, list_2):
    dictionary[key] = value
# original
print(f"Original dictionary: {dictionary}")

# Sort dictionary based on value
dictionary_sorted = dict(sorted(dictionary.items(), key=lambda value: value[1]))
print(f"Sort dictionary by value: {dictionary_sorted}")

# Sort dictionary based on key
dictionary_sorted = dict(sorted(dictionary.items(), key=lambda key: key[0]))
print(f"Sort dictionary by key: {dictionary_sorted}")

python dict sortieren

# dict has no order - use a list to store
l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = list(sorted(l.items(),key=lambda x:x[1],reverse=True))

dict sort

[(k,di[k]) for k in sorted(di.keys())]