PYTHON

get directory of file python

import os 
dir_path = os.path.dirname(os.path.realpath(__file__))

get files in directory python

import os
files_and_directories = os.listdir("path/to/directory")

python get files in directory

from pathlib import Path
for txt_path in Path("/path/folder/directory").glob("*.txt"):
  print(txt_path)

python get files in directory

# Basic syntax:
import glob
list_of_files = glob.glob("search_pattern")
# Where:
#	- the search pattern can be any glob pattern, e.g. /usr/bin/*py* to get the
#		list of files in /usr/bin that contain py

python find directory of file

import os
  
print('File name :    ', os.path.basename(__file__))
print('Directory Name:     ', os.path.dirname(__file__))

python get files in directory

(_, _, filenames) = os.walk(mypath).next() #if you are confident that the walk will return at least one value

python find dir

import os.path
from os import path

def main():

	print ("Is it File?" + str(path.isfile('guru99.txt')))
	print ("Is it File?" + str(path.isfile('myDirectory')))
if __name__== "__main__":
	main()

get the containing dir of a file in python

>>> import os
>>> path=os.path.dirname("C:/folder1/folder2/filename.xml")
>>> path
'C:/folder1/folder2'
>>> os.path.basename(path)
'folder2'