PYTHON

re.sub in python example

import re

result = re.sub(pattern, repl, string, count=0, flags=0);

Python re.sub Examples

result = re.sub('abc',  '',    input)           # Delete pattern abc
result = re.sub('abc',  'def', input)           # Replace pattern abc -> def
result = re.sub(r's+', ' ',   input)           # Eliminate duplicate whitespaces using wildcards
result = re.sub('abc(def)ghi', r'1', input)    # Replace a string with a part of itself

re sub python

# From Grepper Docs
>>> re.sub('-{1,2}', dashrepl, 'pro----gram-files')
'pro--gram files'
>>> re.sub(r'sANDs', ' & ', 'Baked Beans And Spam', flags=re.IGNORECASE)
'Baked Beans & Spam'

how to use re.sub

new_string = re.sub(r"xxx|yyy", "abc", a_string)

Python re.subn()

# Program to remove all whitespaces
import re

# multiline string
string = 'abc 12
de 23 
 f45 6'

# matches all whitespace characters
pattern = 's+'

# empty string
replace = ''

new_string = re.subn(pattern, replace, string) 
print(new_string)

# Output: ('abc12de23f456', 4)

Python re.sub()

re.sub(pattern, replace, string)

re.sub

re.sub(pattern,replacement,string)
re.sub finds all matches of pattern in string and replaces them
with replacement.
#Example
re.sub("[^0-9]","","abcd1234") #Returns 1234

Python RegEx Subn – re.subn()

import re

print(re.subn('ub', '~*', 'Subject has Uber booked already'))

t = re.subn('ub', '~*', 'Subject has Uber booked already',
			flags=re.IGNORECASE)
print(t)
print(len(t))

# This will give same output as sub() would have
print(t[0])

Python re.sub Examples

result = re.sub("(d+) (w+)", r"2 1")
result = re.sub("(?<number>d+) (?<word>w+)", r"g<word> g<number>")