PYTHON

how to remove an element in a list by index python

list = [0, 1, 2, 3, 4, 5]

print(list)
# [0, 1, 2, 3, 4, 5]

del list[0]
print(list)
# [1, 2, 3, 4, 5]
      
del list[-2]
print(list)
# [1, 2, 3, 5]
      
del list[0:2]
print(list)
# [3, 5]

python list remove at index

>>> a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> del a[-1]
>>> a
[0, 1, 2, 3, 4, 5, 6, 7, 8]

remove from list python by index

l = list(range(10))
print(l)
# [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

print(l.pop(0))
# 0

print(l)
# [1, 2, 3, 4, 5, 6, 7, 8, 9]

print(l.pop(3))
# 4

print(l)
# [1, 2, 3, 5, 6, 7, 8, 9]

remove element from list by index

letters = ["a", "b", "c", "d", "e"]
letters.pop(0)
letters.pop(1)
print(letters)
#pop will also return the value if you want to use it

how to remove element from list python by index

>>> l = [1, 2, 43, 3, 4]
>>> l.pop(2) #enter the index as argument
43
>>> l
[1, 2, 3, 4]

python remove by index

a = [0, 1, 2, 3, 4, 5]
el = a.pop(2)

python list remove at index

>>> del a[2:4]
>>> a
[0, 1, 4, 5, 6, 7, 8, 9]

how to remove an item from a certain index in python

arr = [0, 1, 2, 3, 4]
del arr[1]
# arr is now equal to [0, 2, 3, 4]

python list remove at index

a = ['a', 'b', 'c', 'd']
a.pop(1)

# now a is ['a', 'c', 'd']

remove from list python by index

print(l.pop())
# 9

print(l)
# [1, 2, 3, 5, 6, 7]

remove from list python by index

print(l.pop(-2))
# 8

print(l)
# [1, 2, 3, 5, 6, 7, 9]

remove from list python by index

l = list(range(10))
print(l)
# [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

l.clear()
print(l)
# []

remove from list python by index

# print(l.pop(100))
# IndexError: pop index out of range

List Remove At Index

var ls = new List<int>(){1,2,3,4,5};
ls.RemoveAt(2);
// ls elements 1,2,4,5
public void RemoveAt (int index);
Removes the element at the specified index of the List<T>.