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removexa0 python

# xa0 is actually non-breaking space in Latin1 (ISO 8859-1

text = text.replace(u'xa0', u' ')

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python remove xa0

# credit in the source link

import unicodedata

str_hard_space='17xa0kg on 23rdxa0June 2021'
print(str_hard_space)
xa=u'xa0'

if xa in str_hard_space:
    print("xa0 is Found!")
else:
    print("xa0 is not Found!")

# this is the command you are looking for
new_str = unicodedata.normalize("NFKD", str_hard_space)
print (new_str)
if xa in new_str:
    print("xa0 is Found!")
else:
    print("xa0 is not Found!")

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removexa0 python

python remove xa0

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