PYTHON

unzip in python

import zipfile
with zipfile.ZipFile(path_to_zip_file, 'r') as zip_ref:
    zip_ref.extractall(directory_to_extract_to)

how to unzip files using zipfile module python

import zipfile
with zipfile.ZipFile("file.zip","r") as zip_ref:
    zip_ref.extractall("targetdir")

extract zip file python

import zipfile
with zipfile.ZipFile(path_to_zip_file, 'r') as zip_ref:
    zip_ref.extractall(directory_to_extract_to)

unzip python

import shutil
shutil.unpack_archive(filename, extract_dir)

python unzip a zip

# app.py

from zipfile import ZipFile

with ZipFile('Mail3.zip', 'r') as zipObj:
   # Extract all the contents of zip file in different directory
   zipObj.extractall('temp')
   print('File is unzipped in temp folder')

extract zip file in python zipfile

from zipfile import ZipFile
import zipfile

with ZipFile('test.zip') as myzip:
    with myzip.open('Roughwork/textfile.text') as myfile:
        print(myfile.readlines())Copy Code

python extract zip file

from zipfile import ZipFile
import zipfile

myzip = ZipFile('test.zip') 
myzip.extract(member='Roughwork/pretify.html') 

how to extract zip file using python

ZipFile.extractall(path=None, members=None, pwd=None)

python extract zip file

import shutil
import zipfile

# base_name is the name of the zip file you want to create
# format is zip for zip file
# root_dir is the direct path of the folder or file you want to zip
shutil.make_archive(base_name='zip_file_name', format='zip', root_dir='data')

# read zip file from current path
with zipfile.ZipFile(file='zip_file_name.zip', mode='r') as zip_ref:
   # create folder name extract_data in current directory with the extracted data
   zip_ref.extractall(path='extract_data')

# Extract a single file from a zip file
with zipfile.ZipFile(file='zip_file_name.zip', mode='r') as zip_ref:
   # Extract a file name called secrets.dat
   zip_ref.extract(member='secrets.dat')
  
 # extract a list of filename within a zip file
with zipfile.ZipFile(file='zip_file_name.zip', mode='r') as zip_obj:
    # Get list of files names in zip
    filenames = zip_obj.namelist()

    # Iterate over the list of file names in given list & print them
    for filename in filenames:
        print(filename)

zipfile python unzip with path

ZipFile.extract(member, path=None, pwd=None)