PYTHON

Python program to find second largest number in a list

# Python program to find second largest
# number in a list
 
# list of numbers - length of
# list should be at least 2
list1 = [10, 20, 4, 45, 99]
 
mx = max(list1[0], list1[1])
secondmax = min(list1[0], list1[1])
n = len(list1)
for i in range(2,n):
    if list1[i] > mx:
        secondmax = mx
        mx = list1[i]
    elif list1[i] > secondmax and 
        mx != list1[i]:
        secondmax = list1[i]
    elif mx == secondmax and 
        secondmax != list1[i]:
          secondmax = list1[i]
 
print("Second highest number is : ",
      str(secondmax))

write a python program to find the second largest number in a list

list1 = [10, 20, 4, 45, 99]
 
mx = max(list1[0], list1[1])
secondmax = min(list1[0], list1[1])
n = len(list1)
for i in range(2,n):
    if list1[i] > mx:
        secondmax = mx
        mx = list1[i]
    elif list1[i] > secondmax and 
        mx != list1[i]:
        secondmax = list1[i]
    elif mx == secondmax and 
        secondmax != list1[i]:
          secondmax = list1[i]
 
print("Second highest number is : ",
      str(secondmax))