SELECT name, COUNT(*) c FROM table GROUP BY name HAVING c > 1;
SELECT varchar_col
FROM table
GROUP BY varchar_col
HAVING COUNT(*) > 1;
SELECT col, COUNT(col) FROM table_name GROUP BY col HAVING COUNT(col) > 1;
SELECT
col,
COUNT(col)
FROM
table_name
GROUP BY col
HAVING COUNT(col) > 1;
Code language: SQL (Structured Query Language) (sql)
## Find ALL duplicate recods by value (without grouping them by value) ##
# to find the duplicate,
# replace all instances of tableName with your table name
# and all instances of duplicateField with the field name where you look for duplicates
SELECT t1.*
FROM tableName AS t1
INNER JOIN(
SELECT duplicateField
FROM tableName
GROUP BY duplicateField
HAVING COUNT(duplicateField) > 1
)temp ON t1.duplicateField = temp.duplicateField
order by duplicateField
SELECT name, COUNT(*) c FROM table GROUP BY name HAVING c > 1;
SELECT column, COUNT(column) c FROM table GROUP BY column HAVING c > 1;
SELECT firstname,
lastname,
list.address
FROM list
INNER JOIN (SELECT address
FROM list
GROUP BY address
HAVING COUNT(id) > 1) dup
ON list.address = dup.address;