PYTHON

word pattern in python

def wordPattern(pattern, s):
    dict1 = {}
    dict2 = {}

    for key,value in enumerate(list(s.split(" "))):
        if value not in dict1:
            dict1[value]= [key]
        else:
            dict1[value].append(key)

    for key,value in enumerate(pattern):
        if value not in dict2:
            dict2[value]= [key]
        else:
            dict2[value].append(key)

    return (list(dict1.values()) == list(dict2.values()))

word pattern python

import string

def word_to_pattern(word):
    # Stores actual-letter to pattern-placeholder mapping
    mapping = {}

    # ZYXW... so we cap pop letters starting with A from the end
    available_pattern_letters = list(string.ascii_uppercase)[::-1]

    pattern = []
    for letter in word.upper():
        if letter not in string.ascii_uppercase:
            # for punctuation etc
            pattern.append(letter)
            continue
        if letter not in mapping:
            # new letter we haven't seen yet in this word
            mapping[letter] = available_pattern_letters.pop()
        pattern.append(mapping[letter])
    return pattern.join("")

word pattern in python

def wordPattern(pattern, s):
    dict1 = {}
    dict2 = {}

    for key,value in enumerate(list(s.split(" "))):
        if value not in dict1:
            dict1[value]= [key]
        else:
            dict1[value].append(key)

    for key,value in enumerate(pattern):
        if value not in dict2:
            dict2[value]= [key]
        else:
            dict2[value].append(key)

    return (list(dict1.values()) == list(dict2.values()))

word pattern python

import string

def word_to_pattern(word):
    # Stores actual-letter to pattern-placeholder mapping
    mapping = {}

    # ZYXW... so we cap pop letters starting with A from the end
    available_pattern_letters = list(string.ascii_uppercase)[::-1]

    pattern = []
    for letter in word.upper():
        if letter not in string.ascii_uppercase:
            # for punctuation etc
            pattern.append(letter)
            continue
        if letter not in mapping:
            # new letter we haven't seen yet in this word
            mapping[letter] = available_pattern_letters.pop()
        pattern.append(mapping[letter])
    return pattern.join("")